.29=p^2+2p

Solution for .29=p^2+2p equation:

.29=p^2+2p

We move all terms to the left:

.29-(p^2+2p)=0

We add all the numbers together, and all the variables

-(p^2+2p)+0.29=0

We get rid of parentheses

-p^2-2p+0.29=0

We add all the numbers together, and all the variables

-1p^2-2p+0.29=0

a = -1; b = -2; c = +0.29;
Δ = b2-4ac
Δ = -22-4·(-1)·0.29
Δ = 5.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{5.16}}{2*-1}=\frac{2-\sqrt{5.16}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{5.16}}{2*-1}=\frac{2+\sqrt{5.16}}{-2}
$